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問06 physicsCE Q35

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我想問:Lithium cell: 3.6VCapacity: 800 mA hTime( stand-by mode): about 3daysThe figue shows a label on a lithium cell of a mobile phone. The capacity 800mA h indicates the quanity of electric charges that the cell will discharge in3 days when the mobile phone is in stand-by mode. Estimate the... 顯示更多 我想問: Lithium cell: 3.6V Capacity: 800 mA h Time( stand-by mode): about 3days The figue shows a label on a lithium cell of a mobile phone. The capacity 800mA h indicates the quanity of electric charges that the cell will discharge in3 days when the mobile phone is in stand-by mode. Estimate the average power of the cell assuming the voltage remains constant during the discharge. A. 16 mW B. 40 mW C.120 mW D.960 mW copy from 06 CE Physics Q.35

最佳解答:

I = Q / t = 800mAh / 3 ( 24 )h = 1 / 90A P = IV = ( 1 / 90 )( 3.6 ) = 0.04W = 40mW ( Ans : B ) 2008-04-13 00:13:48 補充： http://hk.knowledge.yahoo.com/question/question?qid=7008040401537 You may also refer to my previous answer.

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