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標題:
f. 4 Maths
發問:
If the straight lines y = ((k + 5)(x)/3)) + k and hx + 6y +22 –h = 0intersect at infinitely many points, find the values of h and k.
y = [(k+ 5)(x)/3] +k y = [(k+ 5)/3]x +k hx+ 6y + 22 - h =0 6y = -hx + (h - 22) y = -(h/6)x + [(h - 22)/6] The two st. lines intersect at infinitely many points, i.e. the two st. lines are coincide. (k + 5)/3 = -h/6 ...... [1] k = (h - 22)/6 ...... [2] From [1] : (k+ 5) = -h/2 h = -2k - 10 ...... [3] Put [3] into [2] : k = (-2k - 10 - 22)/6 6k = -2k - 32 8k = -32 k = -4 Put k = -4 into [3] : h = -2(-4) - 10 h = -2 2014-10-12 22:57:05 補充： 謝 謝 知 足 常 樂 師 兄 ！
其他解答:
恭喜土扁師兄升級!!!
f. 4 Maths
發問:
If the straight lines y = ((k + 5)(x)/3)) + k and hx + 6y +22 –h = 0intersect at infinitely many points, find the values of h and k.
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最佳解答:y = [(k+ 5)(x)/3] +k y = [(k+ 5)/3]x +k hx+ 6y + 22 - h =0 6y = -hx + (h - 22) y = -(h/6)x + [(h - 22)/6] The two st. lines intersect at infinitely many points, i.e. the two st. lines are coincide. (k + 5)/3 = -h/6 ...... [1] k = (h - 22)/6 ...... [2] From [1] : (k+ 5) = -h/2 h = -2k - 10 ...... [3] Put [3] into [2] : k = (-2k - 10 - 22)/6 6k = -2k - 32 8k = -32 k = -4 Put k = -4 into [3] : h = -2(-4) - 10 h = -2 2014-10-12 22:57:05 補充： 謝 謝 知 足 常 樂 師 兄 ！
其他解答:
恭喜土扁師兄升級!!!
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