標題:

因式分解(有式) *=次方拜託快一點 (4a-5b)*2-7c(5b-4a)3a-bx+3b-ax4ax-3by+6sy-2bx3p+2q*2-q-6pq-m*2-3mr-3pr-mpx*4+cx*3-2x*3-2cs*2?

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因式分解 (1) (4a-5b)^2-7c(5b-4a) =(4a-5b)^2+7c(4a-5b) =(4a-5b+7c)(4a-5b) (2) 3a-bx+3b-ax =(3a+3b)-(ax+bx) =3(a+b)-x(a+b) =(3-x)(a+b) (3) 4ax-3by+6ay-2bx =(4ax+6ay)-(3by+2bx) =2a(2x+3y)-b(3y+2x) =(2a-b)(2x+3y) (4) 3p+2q^2-q-6pq =(3p-q)+(2q^2-6pq) =(3p-q)+2q(q-3p) =(1-2q)(3p-q) (5) -m^2-3mr-3pr-mp =-(m^2+3mr)-(3pr+mp) =-m(m+3r)-p(m+3r) =-(m+p)(m+3r) (6) x^4+cx^3-2x^3-2cx^2 =(x^4+cx^3)-(2x^3+2cx^2) =x^3(x+2c)-2x^2(x+2c) =(x^3-2x^2)(x+2c)

其他解答:

(4a-5b)^2-7c(5b-4a) =(4a-5c)(4a-5b+7c) 3a-bx+3b-ax =3(a+b)-(a+b)x =(a+b)(3-x) 4ax-3by+6ay-2bx =2x(2a-b)+3y(2a-b) =(2a-b)(2x+3y) 3p+2q^2-q-6pq =q(2q-1)+3p(1-2q) =(2q-1)(q-3p) -m^2-3mr-3pr-mp =-m(m+3r)-p(3r+m) =-(m+3r)(m+p) x*4+cx*3-2x*3-2cx*2 =x^3(x-2)+cx^2(x-2) =x^2(x+c)(x-2)|||||??
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